(i)[3]
Show that $\frac{1}{\sin(x - 60^\circ) + \cos(x - 30^\circ)} \equiv \cosec x$ is true.
(ii)[6]
Hence solve $\frac{2}{\sin(x - 60^\circ) + \cos(x - 30^\circ)} = 3\cot^2 x - 2$ for $0^\circ < x < 360^\circ$.
Mathematics 9709 · AS & A Level · Trigonometry