(i)[3]
Prove the identity $\tan^2\theta - \sin^2\theta = \tan^2\theta\sin^2\theta$.
(ii)[1]
Use this result to show why $\tan\theta > \sin\theta$ for $0^\circ < \theta < 90^\circ$.
Mathematics 9709 · AS & A Level · Trigonometry
Trigonometry — practice question
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This 4-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Express $\tan^2\theta-\sin^2\theta$ in terms of $\sin\theta=s,\cos\theta=c,\tan\theta=t$” …
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