(i)[2]
Show that $2\tan^2\theta\sin^2\theta = 1$ may be rewritten in the form $2\sin^4\theta + \sin^2\theta - 1 = 0$.
(ii)[4]
Hence find the solutions of $2\tan^2\theta\sin^2\theta = 1$ for $0^\circ \leq \theta \leq 360^\circ$.
Mathematics 9709 · AS & A Level · Trigonometry
Trigonometry — practice question
Worked solution & mark scheme
This 6-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Sets up equation $\frac{2\sin^2\theta\sin^2\theta}{1-\sin^2\theta}=1$” …
- Full mark scheme, point by point
- Step-by-step worked solution
- Write your answer & get it marked instantly by AI