(a(i))[3]
Demonstrate that the equation $\tan(x + 45^\circ) = 6\tan x$ may be rewritten as $6\tan^2 x - 5\tan x + 1 = 0$.
(a(ii))[3]
Hence solve the equation $\tan(x + 45^\circ) = 6\tan x$, for $0^\circ < x < 180^\circ$.
Mathematics 9709 · AS & A Level · Trigonometry
Demonstrate that the equation $\tan(x + 45^\circ) = 6\tan x$ may be rewritten as $6\tan^2 x - 5\tan x + 1 = 0$.
Hence solve the equation $\tan(x + 45^\circ) = 6\tan x$, for $0^\circ < x < 180^\circ$.
This 6-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Apply the $\tan(A+B)$ formula to produce an equation in $\tan x$” …