(i)[2]
Show that the equation $3(2\sin x - \cos x) = 2(\sin x - 3\cos x)$ may be rearranged into the form $\tan x = -\tfrac{3}{4}$.
(ii)[2]
Solve the equation $3(2\sin x - \cos x) = 2(\sin x - 3\cos x)$, for $0^\circ \leq x \leq 360^\circ$.
Mathematics 9709 · AS & A Level · Trigonometry
Trigonometry — practice question
Worked solution & mark scheme
This 4-mark question has a full step-by-step worked solution and mark scheme. One marking point: “By expanding and collecting like terms in $3(2\sin x-\cos x)=2(\sin x-3\cos x)$, you should get $6\sin x-3\cos x=2\sin x-6\cos x$ and therefore $4\sin x=-3\cos x$ or an equivalent statement.” …
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