Mathematics 9709 · AS & A Level · Trigonometry

Trigonometry — practice question

The polynomial $p(x)$ is given by $p(x) = 6x^3 + ax^2 + 3x - 10$, with $a$ as a constant. It is stated that $(2x - 1)$ is a factor of $p(x)$.
(a)[5]

Find the value of $a$ and hence factorise $p(x)$ fully.

(b)[2]

Solve $p(\cosec \theta) = 0$ within $-90^\circ < \theta < 90^\circ$.

Worked solution & mark scheme

This 7-mark question has a full step-by-step worked solution and mark scheme. One marking point: Substitute $x=\frac12$, set equal to zero and try to solve

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