Mathematics 9709 · AS & A Level · Trigonometry

Trigonometry — practice question

(a)[5]

First form a quadratic equation in $\cos\theta$, then solve the equation $\tan\theta\,\sin\theta = 1$ for $0^\circ < \theta < 360^\circ$.

(b)[3]

Show that the expression $\frac{\tan\theta}{\sin\theta} - \frac{\sin\theta}{\tan\theta}$ equals $\tan\theta\,\sin\theta$.

Worked solution & mark scheme

This 8-mark question has a full step-by-step worked solution and mark scheme. One marking point: Substitute $\tan\theta=\frac{\sin\theta}{\cos\theta}$ to obtain $\sin^2\theta=\cos\theta$.

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