(main)[5]
Find the values of $\theta$ that satisfy $\frac{\tan\theta + 3\sin\theta + 2}{\tan\theta - 3\sin\theta + 1} = 2$ for $0^\circ \leq \theta \leq 90^\circ$.
Mathematics 9709 · AS & A Level · Trigonometry
Mathematics 9709 · AS & A Level · Trigonometry
Find the values of $\theta$ that satisfy $\frac{\tan\theta + 3\sin\theta + 2}{\tan\theta - 3\sin\theta + 1} = 2$ for $0^\circ \leq \theta \leq 90^\circ$.