In a particular country, the average is that one student in five has blue eyes.
(a(i))[3]
For a random sample of $n$ students, the chance that none of them has blue eyes is below $0.001$. Find the least possible value of $n$.
(a(ii))[4]
For a random sample of $120$ students, find the probability that fewer than $33$ of them have blue eyes.
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This 7-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Forming inequality $(0.8)^n<0.001$” …
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