Mathematics 9709 · AS & A Level · Series

Series — practice question

A geometric progression starts with first term $a$, has common ratio $r$, and its sum to infinity is $S$. A different geometric progression also begins with first term $a$, but its common ratio is $R$ and its sum to infinity is $2S$.
(a)[3]

Show that $r = 2R - 1$.

(b)[4]

It is now stated that the 3rd term of the first progression equals the 2nd term of the second progression. Write $S$ in terms of $a$.

Worked solution & mark scheme

This 7-mark question has a full step-by-step worked solution and mark scheme. One marking point: Apply $S=\dfrac{a}{1-r}$ or an equivalent expression

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