(i)[3]
Show that $v\,\frac{dv}{dx} = 32 - 40x - 48x^2$ while $P$ is moving and the string is stretched.
(ii)[5]
The greatest value of $v$ is $4.5$. Determine the initial value of $v$.
Mathematics 9709 · AS & A Level · Representation of data
Show that $v\,\frac{dv}{dx} = 32 - 40x - 48x^2$ while $P$ is moving and the string is stretched.
The greatest value of $v$ is $4.5$. Determine the initial value of $v$.
This 8-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Therefore, $T = \dfrac{16(1.6 - 0.8 - x)}{0.8} = 16 - 20x$” …