The rod $AB$ has length $1.2\,\mathrm{m}$, with end $A$ freely pivoted at a fixed point. It turns about $A$ in a vertical plane.
(main)[2]
Calculate the angular speed of the rod at the moment when $B$ has speed $0.6\,\mathrm{m\,s^{-1}}$.
Worked solution & mark scheme
This 2-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Applying $v = r\omega$ gives $0.6 = 1.2\omega$” …
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