(a)[3]
Write the equation in the form $y = a(x + b)^2 + c$, with $a$, $b$ and $c$ as constants.
(b)[3]
Hence solve for $x$ in $4x^2 + 20x + 6 = 45$.
(c)[3]
Sketch the graph of $y = 4x^2 + 20x + 6$ and show the coordinates of the stationary point. You do not need to show where the curve meets the $x$- and $y$-axes.