(a)[2]
Use completing the square to determine the exact solutions of the equation $4x^2 - 4x - 1 = 0$.
(b)[3]
Hence solve the equation $4\tan \theta = 4 + \frac{1}{\tan \theta}$ over $0^\circ < \theta < 180^\circ$.
Mathematics 9709 · AS & A Level · Quadratics
Use completing the square to determine the exact solutions of the equation $4x^2 - 4x - 1 = 0$.
Hence solve the equation $4\tan \theta = 4 + \frac{1}{\tan \theta}$ over $0^\circ < \theta < 180^\circ$.
This 5-mark question has a full step-by-step worked solution and mark scheme. One marking point: “By completing the square correctly, you should reach $(x-\frac12)^2=\frac12$” …