The function $f$ is given on $x \in \mathbb{R}$ by $f(x) = x^2 - 6x + c$, where $c$ is a constant. It is known that $f(x) > 2$ for every value of $x$.
(main)[4]
Find the set of all values that $c$ may take.
Worked solution & mark scheme
This 4-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Complete the square so that you get $(x-3)^2-9+c>2$” …