A and $B$ are two fixed points on a vertical axis, with $A$ $0.6\text{ m}$ above $B$. A particle $P$ of mass $0.3\text{ kg}$ is joined to $A$ by a light inextensible string of length $0.5\text{ m}$. The particle $P$ is also joined to $B$ by a light elastic string with modulus of elasticity $46\text{ N}$. Particle $P$ travels with constant angular speed $8\,\text{rad s}^{-1}$ in a horizontal circle whose centre is the mid-point of $AB$.
(i)[2]
Calculate the speed of $P$.
(ii)[7]
Calculate the tension in the string $BP$ and hence determine the natural length of this string.
Worked solution & mark scheme
This 9-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Apply Pythagoras: $0.3^2+r^2=0.5^2$, leading to $r=0.4$” …