Mathematics 9709 · AS & A Level · Probability

Probability — practice question

On a smooth horizontal surface, fixed points $O$ and $A$ are $0.8\,\text{m}$ apart. A particle $P$ with mass $0.25\,\text{kg}$ is projected horizontally from $A$ at $3\,\text{m s}^{-1}$ in the direction away from $O$. When the displacement of $P$ from $O$ is $x\,\text{m}$, its speed is $v\,\text{m s}^{-1}$. The motion of $P$ is resisted by a force of magnitude $k v^2 x^{-2}\,\text{N}$.
(i)[1]

Show that, in this situation, $\frac{dv}{dx} = -4k v^2 x^{-2}$.

(ii)[5]

Give $v$ as a function of $k$ and $x$.

Worked solution & mark scheme

This 6-mark question has a full step-by-step worked solution and mark scheme. One marking point: Finds $0.25v\frac{dv}{dx}=-kv^2x^{-2}\Rightarrow\frac{dv}{dx}=-4kv^2x^{-2}$

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