From a position on level ground, a particle is launched at speed $15\,\text{m s}^{-1}$ at an angle of $\theta^\circ$ above the horizontal. It lands back on the ground $2\,\text{s}$ later.
(i)[2]
Determine $\theta$.
(ii)[4]
Calculate the time after projection when the particle is moving at an angle of $20^\circ$ below the horizontal.
Worked solution & mark scheme
This 6-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Writes vertical equation $-15\sin\theta=15\sin\theta-2g$” …