One end of a light elastic string whose natural length is $0.8\,\text{m}$ and whose modulus of elasticity is $24\,\text{N}$ is fixed at point $O$. The opposite end is connected to a particle $P$ of mass $0.3\,\text{kg}$. From a point $1.2\,\text{m}$ vertically beneath $O$, $P$ is projected vertically upwards at speed $4\,\text{m s}^{-1}$.
(i)[5]
Calculate the speed of the particle at the point where its acceleration is zero.
(ii)[3]
Show that, as it rises with constant deceleration, the particle travels $1.2\,\text{m}$.
Worked solution & mark scheme
This 8-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Applies $T = \frac{\lambda x}{L}$: $0.3g = 24e$” …