Mathematics 9709 · AS & A Level · Probability

Probability — practice question

A uniform rigid rod $AB$ with length $1.2\,\text{m}$ and weight $8\,\text{N}$ carries a particle of weight $2\,\text{N}$ fixed at endpoint $B$. Endpoint $A$ is attached by a free hinge to a fixed point. One end of a light elastic string, whose natural length is $0.8\,\text{m}$ and modulus of elasticity is $20\,\text{N}$, is fastened to the hinge. The string passes over a small smooth pulley $P$ fixed $0.8\,\text{m}$ vertically above the hinge. The other end is connected to a small light smooth ring $R$ that can move along the rod. The system is in equilibrium, with the rod making an angle $\theta^{\circ}$ to the vertical (see diagram).
(i)[1]

Show that the tension in the string comes to $20\sin\theta\,\text{N}$.

(ii)[1]

Explain why the part of the string attached to the ring is perpendicular to the rod.

(iii)[3]

Find $\theta$.

Worked solution & mark scheme

This 5-mark question has a full step-by-step worked solution and mark scheme. One marking point: Applies the tension formula $T = \frac{20(0.8\sin\theta)}{0.8}$, hence $20\sin\theta$

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