Mathematics 9709 · AS & A Level · Probability

Probability — practice question

One end of a light elastic string, whose modulus of elasticity is $15\,\text{N}$, is fastened to a fixed point $A$, which lies $2\,\text{m}$ directly above a fixed small smooth ring $R$. The string’s natural length is $2\,\text{m}$, and it passes through $R$. Its other end is attached to a particle $P$ of mass $m\,\text{kg}$, and $P$ travels at constant angular speed $\omega\,\text{rad s}^{-1}$ around a horizontal circle with centre $0.4\,\text{m}$ vertically below the ring. $PR$ forms an acute angle $\theta$ with the vertical (see diagram).
(i)[4]

Show that the tension in the string is $\frac{3}{\cos\theta}\,\text{N}$ and hence determine $m$.

(ii)[4]

Show that $\omega$ is independent of $\theta$.

(iii)[4]

Find the value of $\theta$.

Worked solution & mark scheme

This 12-mark question has a full step-by-step worked solution and mark scheme. One marking point: Applies $T = \frac{\lambda e}{2}$ to write $T = \frac{15(0.4/\cos\theta)}{2}$

  • Full mark scheme, point by point
  • Step-by-step worked solution
  • Write your answer & get it marked instantly by AI