Particles $P$ and $Q$, with masses $0.4\text{ kg}$ and $0.2\text{ kg}$ respectively, are fixed to the two ends of a light inextensible string. $P$ rests on a horizontal table, while the string runs over a small smooth pulley at the table’s edge. The string is stretched tight, and the section attached to $Q$ hangs vertically. The coefficient of friction between $P$ and the table is $0.5$. $Q$ is given a vertically downward speed of $5\text{ m s}^{-1}$, and after $t\text{ s}$ from the instant of projection the particles have speed $v\text{ m s}^{-1}$. Each particle experiences a resisting force of magnitude $0.9v\text{ N}$. Particle $P$ does not reach the pulley.
(i)[4]
Show that $\frac{dv}{dt} = -3v$.
(ii)[7]
Determine the value of $t$ when the particles have speed $2.5\text{ m s}^{-1}$ and the distance each particle has moved by that time.
Worked solution & mark scheme
This 11-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Sets up a correct N2L equation at the rounded corner, giving $0.6\,dv/dt=0.2g-0.4g\times 0.5-1.8v$.” …