Mathematics 9709 · AS & A Level · Probability

Probability — practice question

A particle $P$ with mass $0.2\,\text{kg}$ is let go from rest and moves vertically downward. At time $t\,\text{s}$ after release, its speed is $v\,\text{m s}^{-1}$. A resisting force of magnitude $0.8v\,\text{N}$ acts on $P$.
(i)[2]

Show that the acceleration for $P$ is $(10 - 4v)\,\text{m s}^{-2}$.

(ii)[5]

Find the value of $v$ at $t = 0.6$.

Worked solution & mark scheme

This 7-mark question has a full step-by-step worked solution and mark scheme. One marking point: The equation of motion is $0.2\, \dfrac{dv}{dt} = 0.2g - 0.8v$.

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