(i)[6]
Show that $\frac{dv}{dt} = 10 - 0.2v$. Hence find an expression for $v$ in terms of $t$.
(ii)[4]
Since the ball reaches the ground at $t = 2$, calculate $h$.
Mathematics 9709 · AS & A Level · Probability
Probability — practice question
A ball with mass $0.05\text{ kg}$ is let go from rest at a height $h\text{ m}$ above the ground. After $t\text{ s}$ from release, its downward velocity is $v\text{ m s}^{-1}$. The air resistance acts opposite to the motion with a force of magnitude $0.01v\text{ N}$.
Worked solution & mark scheme
This 10-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Applies Newton’s Second Law to obtain $0.05\frac{dv}{dt} = 0.05g - 0.01v$” …
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