A light elastic string has natural length $0.4\text{ m}$ and modulus of elasticity $20\text{ N}$; one end is fixed at point $O$, and the other end is connected to a particle $P$ of mass $0.25\text{ kg}$. $P$ hangs in equilibrium beneath $O$.
(i)[2]
Calculate the distance $OP$.
(ii)[3]
Particle $P$ is raised and then released from rest at $O$. Calculate the speed of $P$ as it passes through the equilibrium position.
(iii)[3]
Calculate the greatest value reached by the distance $OP$ in the subsequent motion.
Worked solution & mark scheme
This 8-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Applies $T = \frac{\lambda x}{L}$ and writes $0.25g = \frac{20e}{0.4}$” …