Particle $P$ is launched from point $O$ on a horizontal plane with speed $26\,\text{m s}^{-1}$ at an angle of $30^\circ$ above the horizontal.
(i)[4]
At the instant when the vertical component of the velocity of $P$ is $5\,\text{m s}^{-1}$ downwards, determine the direction of motion of $P$ and its height above the plane.
(ii)[3]
At point $A$, where $P$ meets the plane, calculate the time for $P$ to travel from $O$ to $A$ and the distance $OA$.
Worked solution & mark scheme
This 7-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Applies $\tan \alpha = \frac{5}{26\cos30^{\circ}}$” …