Mathematics 9709 · AS & A Level · Probability

Probability — practice question

(main)[5]

A particle is launched at speed $V\,\text{m s}^{-1}$ at an angle of $\theta^\circ$ above the horizontal. After $4\,\text{s}$, its speed is $16\,\text{m s}^{-1}$ and its direction of motion is $30^\circ$ above the horizontal. Determine $V$ and $\theta$.

Worked solution & mark scheme

This 5-mark question has a full step-by-step worked solution and mark scheme. One marking point: Horizontal component: $V\cos\theta = 16\cos30 = 8\sqrt{3}$

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