A particle $P$ with mass $0.4\,\text{kg}$ is fastened to one end of a light elastic string whose natural length is $0.5\,\text{m}$ and modulus of elasticity is $6\,\text{N}$. The opposite end of the string is fixed at point $O$. The particle $P$ is let go from rest at the point $(0.5 + x)\,\text{m}$ vertically below $O$. The particle $P$ then comes to instantaneous rest at $O$.
(i)[3]
Find the value of $x$.
(ii)[5]
Find the greatest speed of $P$.
Worked solution & mark scheme
This 8-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Energy equation: $0.4g(0.5+x) = \frac{6x^2}{2\times0.5}$” …