Mathematics 9709 · AS & A Level · Probability

Probability — practice question

A particle $P$ with mass $0.4\,\text{kg}$ is launched horizontally from point $O$ across a smooth horizontal plane. After $t\,\text{s}$ have elapsed since projection, the velocity of $P$ is $v\,\text{m s}^{-1}$. A force of magnitude $0.8t\,\text{N}$ acting away from $O$ is applied to $P$, while a force of magnitude $2e^{-t}\,\text{N}$ acts opposite to the motion of $P$.
(i)[2]

Show that $\frac{dv}{dt} = 2t - 5e^{-t}$.

(ii)[3]

Given that $v = 8$ when $t = 1$, express $v$ as a function of $t$.

(iii)[2]

Find the speed of projection of $P$.

Worked solution & mark scheme

This 7-mark question has a full step-by-step worked solution and mark scheme. One marking point: Uses Newton’s Second Law horizontally: $0.4\dfrac{dv}{dt} = 0.8t - 2e^{-t}$

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