Mathematics 9709 · AS & A Level · Probability

Probability — practice question

A small ball $B$ is launched from point $O$ on level ground in the direction of point $A$, which is $12\,\text{m}$ above the ground. After $0.9\,\text{s}$, $B$ has moved $20\,\text{m}$ horizontally and lies directly beneath $A$ (see diagram).
(i)[4]

Find the angle of projection and the speed of projection of $B$.

(ii)[2]

Calculate the distance $AB$ at the moment $B$ is vertically below $A$.

Worked solution & mark scheme

This 6-mark question has a full step-by-step worked solution and mark scheme. One marking point: Use of $\tan \theta = \frac{12}{20}$ to determine the angle of projection $\theta$

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