A particle of mass $0.3\,\text{kg}$ is fastened to one end of a light elastic string with natural length $0.8\,\text{m}$ and modulus of elasticity $6\,\text{N}$. The other end of the string is fixed at point $O$. The particle is projected vertically downwards from $O$ with initial speed $2\,\text{m s}^{-1}$.
(i)[5]
Calculate the particle’s greatest speed during its downward motion.
(ii)[3]
Find the greatest distance of the particle below $O$.
Worked solution & mark scheme
This 8-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Applies $T = \lambda x/L$: $0.3g = 6e/0.8$” …