A particle $P$ with mass $0.15\,\text{kg}$ is attached to one end of a light elastic string whose natural length is $0.4\,\text{m}$ and modulus of elasticity is $12\,\text{N}$. The other end of the string is fixed at point $A$. Particle $P$ travels in a horizontal circle with its centre directly below $A$, while the string makes an angle of $\theta^\circ$ with the vertical and $AP = 0.5\,\text{m}$.
(i)[5]
Find the angular speed of $P$ and the value of $\theta$.
(ii)[4]
Calculate the difference between the elastic potential energy stored in the string and the kinetic energy of $P$.
Worked solution & mark scheme
This 9-mark question has a full step-by-step worked solution and mark scheme.