A particle is launched at a speed of $12\text{ m s}^{-1}$ from a point on level ground. It returns to the ground $1.6\text{ s}$ later.
(main)[2]
Calculate the projection angle.
Worked solution & mark scheme
This 2-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Set up equation $-12\sin\theta = 12\sin\theta - 1.6g$” …