Particle $P$ is launched from point $O$ with speed $50\,\text{m s}^{-1}$ at an angle of $40^\circ$ above the horizontal. At $2.5\,\text{s}$ after launch, calculate
(i)[3]
the magnitude of the velocity of $P$.
(ii)[4]
the angle made by $OP$ with the horizontal.
Worked solution & mark scheme
This 7-mark question has a full step-by-step worked solution and mark scheme. One marking point: “$v_y=50\sin40-2.5g$” …