A particle with mass $0.2\,\text{kg}$ is projected vertically downwards at an initial speed of $4\,\text{m s}^{-1}$. While it is descending, a resisting force of magnitude $0.09v\,\text{N}$ acts vertically upwards on the particle, where $v\,\text{m s}^{-1}$ represents the particle's downward velocity at time $t$ after it has been set in motion.
(i)[1]
Show that the particle's acceleration is $(10 - 0.45v)\,\text{m s}^{-2}$.
(ii)[5]
Find the value of $v$ when $t = 1.5$.
Worked solution & mark scheme
This 6-mark question has a full step-by-step worked solution and mark scheme. One marking point: “$a=10-0.45v$” …