Points $A$ and $B$ are $10\,\text{m}$ apart on one horizontal plane. Particle $P$ begins from rest at $A$ and travels straight towards $B$ with constant acceleration $0.5\,\text{m s}^{-2}$. A second particle $Q$ moves straight towards $A$ at constant speed $0.75\,\text{m s}^{-1}$, and it passes through $B$ at the moment that $P$ starts to move. $T$ s after this moment, particles $P$ and $Q$ collide.
(i)[4]
Find $T$.
(ii)[1]
Find the speed of $P$ immediately before the collision.
Worked solution & mark scheme
This 5-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Use $s = ut + \tfrac{1}{2}at^2$ to obtain $\tfrac{1}{2}(0.5)T^2 + 0.75T = 10$” …