The positive numbers $p$ and $q$ satisfy $\ln\left(\frac{p}{q}\right) = a$ and $\ln(q^2p) = b$.
(main)[4]
Write $\ln(p^7q)$ in terms of $a$ and $b$.
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This 4-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Derive $\ln p-\ln q=a$” …
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