(a)[1]
Sketch the velocity-time graph for the athlete’s motion.
(b)[4]
Find $T$ in terms of $V$, and hence show that $7V^2 - 492V + 2700 = 0$.
(c)[2]
Find the value of $V$, and justify your answer.
Mathematics 9709 · AS & A Level · Kinematics of motion in a straight line
Sketch the velocity-time graph for the athlete’s motion.
Find $T$ in terms of $V$, and hence show that $7V^2 - 492V + 2700 = 0$.
Find the value of $V$, and justify your answer.
This 7-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Accurate velocity-time graph (trapezium beginning and ending on horizontal axis)” …