(a)[1]
Show that $V = 4.8$.
(b)[3]
Sketch a velocity-time graph for this motion.
(c)[2]
Find an expression, in terms of $t$, for the particle's velocity when $15 \leq t \leq 20$.
(d)[4]
Find the total distance travelled by the particle.
Mathematics 9709 · AS & A Level · Kinematics of motion in a straight line
Kinematics of motion in a straight line — practice question
A particle travels along a straight line. It begins at rest at time $t = 0$ and has acceleration $0.6\,\text{m s}^{-2}$ for $4\,\text{s}$, so it attains a speed of $V\,\text{m s}^{-1}$. It then continues at $V\,\text{m s}^{-1}$ for $11\,\text{s}$, before slowing uniformly and coming to rest after another $5\,\text{s}$.
Worked solution & mark scheme
This 10-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Carry out the correct integration of $a=0.6t$ to obtain $v=0.3t^2$, then apply the limits” …
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