Mathematics 9709 · AS & A Level · Kinematics of motion in a straight line

Kinematics of motion in a straight line — practice question

A particle $P$ travels along a straight line from a point $O$ and is brought to rest $14\,\text{s}$ afterwards. If $t\,\text{s}$ have elapsed since leaving $O$, the velocity $v\,\text{m s}^{-1}$ of $P$ is defined by $v = pt^2 - qt \quad 0 \leq t \leq 6,$ $v = 63 - 4.5t \quad 6 \leq t \leq 14,$ where $p$ and $q$ are positive constants. The acceleration of $P$ is zero when $t = 2$.
(a)[3]

Assuming there are no instantaneous changes in velocity, determine $p$ and $q$.

(b)[3]

Draw the velocity-time graph.

(c)[5]

Determine the total distance covered by $P$ in the $14\,\text{s}$.

Worked solution & mark scheme

This 11-mark question has a full step-by-step worked solution and mark scheme. One marking point: Differentiate $v$ to get $a=2pt-q$

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