Mathematics 9709 · AS & A Level · Kinematics of motion in a straight line

Kinematics of motion in a straight line — practice question

A particle is launched vertically upwards at a speed of $40\,\text{m s}^{-1}$ next to a building of height $h$ m.
(a)[4]

Since the particle is above the level of the top of the building for $4\,\text{s}$, determine $h$.

(b)[4]

A second particle is projected vertically upwards from the top of the building with speed $20\,\text{m s}^{-1}$, 1 second after the first particle is projected. If $t\,\text{s}$ is the time measured from the first projection, determine the value of $t$ when the two particles are at the same height above the ground.

Worked solution & mark scheme

This 8-mark question has a full step-by-step worked solution and mark scheme. One marking point: Apply $v = u + at$ and $40 - gt = 0$ to deduce $t = 4$

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