Mathematics 9709 · AS & A Level · Kinematics of motion in a straight line

Kinematics of motion in a straight line — practice question

Particles $A$ and $B$ travel along the same vertical straight line. $A$ is launched vertically upwards from the ground at $20\,\text{m s}^{-1}$. After 1 second, $B$ is released from rest from a height of $40\,\text{m}$.
(i)[4]

Find the height above the ground where the two particles meet.

(ii)[3]

Find the difference between the speeds of the two particles at the moment of collision.

Worked solution & mark scheme

This 7-mark question has a full step-by-step worked solution and mark scheme. One marking point: Valid height expressions, for example $h_A = 20t - \tfrac12\times10t^2$ and $h_B = \tfrac12\times10(t-1)^2$

  • Full mark scheme, point by point
  • Step-by-step worked solution
  • Write your answer & get it marked instantly by AI