Mathematics 9709 · AS & A Level · Kinematics of motion in a straight line

Kinematics of motion in a straight line — practice question

Particle $P$ is launched vertically upwards from horizontal ground at a speed of $12\,\text{m s}^{-1}$.
(i)[2]

Determine how long $P$ takes to return to the ground.

(ii)[4]

Let $t$ represent the number of seconds after $P$ is projected. At $t = 1$, a second particle $Q$ is launched vertically upwards at $10\,\text{m s}^{-1}$ from a point $5\,\text{m}$ above the ground. $P$ and $Q$ travel along different vertical lines. Determine the set of $t$ values for which the two particles are moving in the same direction.

Worked solution & mark scheme

This 6-mark question has a full step-by-step worked solution and mark scheme. One marking point: Applying $s = ut + \tfrac12 at^2$ or an equivalent relation to reach an equation like $12t - \tfrac12 gt^2 = 0$

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