Mathematics 9709 · AS & A Level · Kinematics of motion in a straight line

Kinematics of motion in a straight line — practice question

A particle P leaves from rest and travels in a straight line for 18 s. During the first 8 s, P has constant acceleration 0.25 m s^-2. After that, P’s velocity, v m s^-1 at time t seconds after the motion began, is given by v = -0.1t^2 + 2.4t - k, where 8 ≤ t ≤ 18 and k is a constant.
(i)[2]

Determine v when t = 8 and hence determine k.

(ii)[2]

Determine the maximum velocity of P.

(iii)[3]

Determine the displacement of P from its starting position when t = 18.

Worked solution & mark scheme

This 7-mark question has a full step-by-step worked solution and mark scheme. One marking point: Work out v(8) = 0.25 × 8 = 2

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