(a)[3]
Find the value of $t$ for point $B$.
(b)[5]
Find the distance travelled from $A$ to the point where the particle’s acceleration is zero again.
Mathematics 9709 · AS & A Level · Kinematics of motion in a straight line
Kinematics of motion in a straight line — practice question
A particle travels in a straight line, beginning from rest at $A$ and stopping instantaneously at $B$. At time $t$ after it has left $A$, its acceleration is $a\,\text{m s}^{-2}$, where $a = 6t^2 - 2t$.
Worked solution & mark scheme
This 8-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Integrate the expression $v=\int(6t^{\frac{1}{2}}-2t)\,dt$” …
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