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Find the time taken from projection for $P$ to reach the ground.
Mathematics 9709 · AS & A Level · Kinematics of motion in a straight line
Kinematics of motion in a straight line — practice question
A particle $P$ is launched vertically upwards at speed $24\,\text{m s}^{-1}$ from a position $5\,\text{m}$ above ground level.
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This 3-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Use the equation $s = ut + \frac{1}{2}at^2$ so that $-5 = 24t - 5t^2$ is obtained” …
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