Mathematics 9709 · AS & A Level · Kinematics of motion in a straight line

Kinematics of motion in a straight line — practice question

A vehicle travels along a straight line. Its velocity $v \text{ m s}^{-1}$ at time $t \text{ s}$ after it begins is given by $$v = A(t - 0.05t^{2}) \text{ for } 0 \le t \le 15,$$ $$v = \frac{B}{t^{2}} \text{ for } t > 15,$$ where $A$ and $B$ are constants. The distance the vehicle covers from $t = 0$ to $t = 15$ is $225 \text{ m}$.
(i)[5]

Determine $A$ and show that $B = 3375$.

(ii)[3]

Find a formula in terms of $t$ for the vehicle's total distance travelled when $t > 15$.

(iii)[3]

Determine the speed of the vehicle when the total distance covered is $315 \text{ m}$.

Worked solution & mark scheme

This 11-mark question has a full step-by-step worked solution and mark scheme. One marking point: Integrates $v_1$ to obtain $s_1$.

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