Mathematics 9709 · AS & A Level · Kinematics of motion in a straight line

Kinematics of motion in a straight line — practice question

A small rocket is launched straight up from ground level from rest, and it travels with constant acceleration. After $10\,\text{s}$, the rocket is at a height of $200\,\text{m}$.
(i)[4]

Show that the rocket’s speed after $10\,\text{s}$ is $40\,\text{m s}^{-1}$, and determine the rocket’s acceleration during the first $10\,\text{s}$.

(ii)[2]

After $10\,\text{s}$, the rocket’s fuel has stopped burning and there is no upward force acting on the rocket. Find the maximum height above ground level reached by the rocket.

(iii)[4]

Determine the total time from the instant the rocket is launched until it returns to the ground.

(c(iii))[4]

Determine the total time from the instant the rocket is launched until it returns to the ground.

Worked solution & mark scheme

This 14-mark question has a full step-by-step worked solution and mark scheme. One marking point: Application of $s = \tfrac12 (u+v)t$: $200 = \tfrac12 (0+v) \times 10$

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