Mathematics 9709 · AS & A Level · Kinematics of motion in a straight line
Kinematics of motion in a straight line — practice question
A small rocket is launched straight up from ground level from rest, and it travels with constant acceleration. After $10\,\text{s}$, the rocket is at a height of $200\,\text{m}$.
(i)[4]
Show that the rocket’s speed after $10\,\text{s}$ is $40\,\text{m s}^{-1}$, and determine the rocket’s acceleration during the first $10\,\text{s}$.
(ii)[2]
After $10\,\text{s}$, the rocket’s fuel has stopped burning and there is no upward force acting on the rocket. Find the maximum height above ground level reached by the rocket.
(iii)[4]
Determine the total time from the instant the rocket is launched until it returns to the ground.
(c(iii))[4]
Determine the total time from the instant the rocket is launched until it returns to the ground.
Worked solution & mark scheme
This 14-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Application of $s = \tfrac12 (u+v)t$: $200 = \tfrac12 (0+v) \times 10$” …