Mathematics 9709 · AS & A Level · Integration

Integration — practice question

The curve is defined by $y=\sqrt{6x+5}$. The shaded area is enclosed by the curve, the $x$-axis and the lines $x=a$ and $x=2a$, where $a$ is a positive constant. When this shaded area is rotated through $360^\circ$ about the $x$-axis, a solid is produced. The solid has volume, $V$, with $V>46\pi$.
(a)[4]

Show that the inequality $9a^2+5a-46>0$ holds.

(b)[3]

Determine the range of possible values of $a$.

Worked solution & mark scheme

This 7-mark question has a full step-by-step worked solution and mark scheme. One marking point: $V=\pi\int_a^{2a}(6x+5)\,dx$

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