(a)[3]
Determine the quotient and remainder when $x^4 + 16$ is divided by $x^2 + 4$.
(b)[5]
Hence demonstrate that $\displaystyle \int_{2}^{2\sqrt{3}} \frac{x^4 + 16}{x^2 + 4} \, dx = \frac{4}{3}(\pi + 4)$.
Mathematics 9709 · AS & A Level · Integration
Determine the quotient and remainder when $x^4 + 16$ is divided by $x^2 + 4$.
Hence demonstrate that $\displaystyle \int_{2}^{2\sqrt{3}} \frac{x^4 + 16}{x^2 + 4} \, dx = \frac{4}{3}(\pi + 4)$.